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Limx->3- -5x^2+1/x-3
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Limx->3- -5x^2+1/x-3

User Wesgur
by
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1 Answer

7 votes

Answer: ∞

Explanation:


\displaystyle\\ \lim_(x \to 3-0) (-5x^2+1)/(x-3) =\\\\ (-5(3-0)^2+1)/(3-0-3) =\\\\(-5(3)^2+1)/(-0)=\\\\(-5(9)+1)/(-0)=\\\\(-45+1)/(-0) =\\\\(-44)/(-0) =\\\\(44)/(0) =\\\\\infty

User Nijia
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