Question

What is the speed of each ball when they are each 4.10 m above the ground?

Answer 1

12.3 m/s is the correct answer

Answer 2

12.3 m/s

Explanation:

The vertical speed can be calculated by means of the following equation:

`v^2_{^{}y}=u^2_y+2\cdot a\cdot s`

The speed in both cases is the same, since the angle remains the same.

We can calculate the initial speed in y since we know the angle, the value s would be the height, therefore, we substitute and calculate the final speed in y:

`\begin{gathered} v^2_y=(11\cdot\sin 50)^2+2\cdot(-9.8)\cdot(-4.1) \\ v^2_y=151.36 \\ v_y=\sqrt[]{151.36} \\ v_y=12.3\text{ m/s} \end{gathered}`

The speed would be 12.3 m/s in both cases