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Write a Lena near equation of the line passing through the points (-2,4)(4,16)

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The given points are (-2, 4) and (4, 16).

First, we use the slope formula.


m=(y_2-y_1)/(x_2-x_1)

Let's replace the given points.


m=(16-4)/(4-(-2)))(12)/(4+2)=(12)/(6)=2

Once we have the slope, we use the point-slope formula to find the equation.


y-y_1=m(x-x_1)

Let's replace the slope m = 2, and the point (-2,4).


\begin{gathered} y-4=2(x-(-2)) \\ y-4=2x+4 \\ y=2x+4+4 \\ y=2x+8 \end{gathered}

Hence, the equation is y = 2x + 8.

User Mr Griever
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