73.6k views
4 votes
For resistors of 10 Ω, 15 Ω and 20 Ω, two resistors are connected in parallel and one in series. Calculate all the possible total resistance values.

User Mehrnoosh
by
8.8k points

1 Answer

6 votes

Given the resistors:

10Ω, 15 Ω and 20 Ω

Two resistors are connected in parallel and one in series.

Let's calculate all the possible total resistance values.

When resistors are connected in parallel, the equivalent resistance is:


(1)/(R_4)=(1)/(R_1)+(1)/(R_2)

After finding the equivalent resistance value in parellel, we now add the resistance value with the resistance in series:


R_(eq)=R_4+R_3

• When 10Ω and 15Ω are connected in parallel and 20Ω in series, we have:

R1 = 10 Ω

R2 = 15 Ω

R3 = 20 Ω


\begin{gathered} (1)/(R_4)=(1)/(10)+(1)/(15)=(3+2)/(30)=(5)/(30)=(1)/(6) \\ \\ R_4=6\Omega \\ \\ \text{Now to find the total resistance, we have:} \\ R_(eq)=R_4+R_3=\text{ 6 }\Omega\text{ + 20}\Omega \\ \\ R_(eq)=26\text{ }\Omega \end{gathered}

When 10Ω and 15Ω are connected in parallel and 20Ω in series the total resistance is 26 Ω.

• When 10Ω and 20Ω are connected in parallel and 15Ω in series, we have:

R1 = 10 Ω

R2 = 20 Ω

R3 = 15 Ω

Hence, we have:


\begin{gathered} (1)/(R_4)=(1)/(R_1)+(1)/(R_2)=(1)/(10\Omega)+(1)/(20\Omega)=(2+1)/(20)=(3)/(20)\Omega \\ \\ R_4=(20)/(3)\Omega\approx6.7\Omega \\ \\ \text{Thus, we have:} \\ R_(eq)=R_4+R_3=6.7\Omega+15\Omega=21.7\Omega \end{gathered}

When 10Ω and 20Ω are connected in parallel and 15Ω in series the total resistance is 21.7 Ω.

• When 20Ω and 15Ω are connected in parallel and 10Ω in series, we have:

R1 = 20 Ω

R2 = 15 Ω

R3 = 10 Ω

Thus, we have:


\begin{gathered} (1)/(R_4)=(1)/(R_1)+(1)/(R_2)=(1)/(20)+(1)/(15)=(3+4)/(60)=(7)/(60) \\ \\ R_4=(60)/(7)\approx8.6\Omega \\ \\ R_(eq)=R_4+R_3=8.6+10=18.6\Omega \end{gathered}

When 20Ω and 15Ω are connected in parallel and 10Ω in series the total resistance is 18.6Ω.

ANSWER:

• When 10Ω and 15Ω are connected in parallel and 20Ω in series the total resistance is 26 Ω.

,

• When 10Ω and 20Ω are connected in parallel and 15Ω in series the total resistance is 21.7 Ω.

,

• When 20Ω and 15Ω are connected in parallel and 10Ω in series the total resistance is 18.6Ω.

User Dave Gamble
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.