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Find the vertex and write the quadratic function in vertex form (which our OpenStax textbook also calls the standard form).f(x)=x^2−10 x + 74 Give the vertex. Enter your answer as a point (a,b) .Vertex:Enter the coordinates of the vertex to write f(x) in vertex form:f(x)=(x− )^2+

User Crosswind
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1 Answer

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We have the parabola equation in standard form:


y=ax^2+bx+c

and we need to convert it into a vertex form:


y=A(x-h)^2+k

In order to obtain it, we can note that


f(x)=x^2-10x+74

can be rewritten as


f(x)=(x-5)^2-25+74

this is because


(x-5)^2=x^2-10x+25

From our last result, we have


f(x)=(x-5)^2+49

By comparing this result with the general vertex form, we can note that


\begin{gathered} A=1 \\ h=5 \\ k=49 \end{gathered}

Therefore, the equation in vertex form is given by:


f(x)=(x-5)^2+49

with vertex:


(h,k)=(5,49)

User GuyFawkes
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