Answer:
The acceleration of the jet when it speeds up = 7.5 m/s²
Step-by-step explanation:
The initial speed, u = 100 m/s
Distance travelled, s = 2. km
s = 2 x 1000m
s = 2000 m
Final speed, v = 200 m/s
The acceleration is found by using the equation of motion below
![v^2=u^2+2as](https://img.qammunity.org/2023/formulas/physics/college/upn5ri4zo1ndjb2dqdsoklm8yemq8tpp79.png)
Substitute v = 200 m/s, u = 100 m/s, s = 2000 m
![\begin{gathered} 200^2=100^2+2* a*2000 \\ 40000=10000+4000a \\ 4000a=30000 \\ a=(30000)/(4000) \\ a=7.5m/s^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/oe8kenwei5rkry749az9mq8en01akl6swb.png)
The acceleration of the jet when it speeds up = 7.5 m/s²