Question

A large rectangle has an area of 5x^2 + 3x - 2. If I place a smaller rectangle, with an area of 2x^2 + x + 6, over the larger rectangle. What area of the larger rectangle will still be visible?

Answer 1

(5x^2 + 3x - 2) - (2x^2 + x + 6) = 3x^2 + 2x - 8

Explanation: