A large rectangle has an area of 5x^2 + 3x - 2. If I place a smaller rectangle, with an area of 2x^2 + x + 6, over the larger rectangle. What area of the larger rectangle will still be visible?

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asked Jul 13, 2023 160k views

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A large rectangle has an area of 5x^2 + 3x - 2. If I place a smaller rectangle, with an area of 2x^2 + x + 6, over the larger rectangle. What area of the larger rectangle will still be visible?

Mathematics
high-school

Omniwombat asked

by Omniwombat

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1 Answer

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Answer:

(5x^2 + 3x - 2) - (2x^2 + x + 6) = 3x^2 + 2x - 8

Explanation:

Lukew answered Jul 18, 2023

by Lukew

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