Question

Which accelerates from 0 to 2.50 m/s in 9.0 seconds

Answer 1

Acceleration of the cyclist is 2.1 m/s^2

The acceleration of the cyclist is not higher, that of the car is higher (2.8 m/s^2)

Explanation:

Given:

u1 = 0 m/s

v1 = 10.7 m/s

t1 = 5.1 sec

u2 = 0 m/s

v2 = 25 m/s

t2 = 9 sec

We can calculate the value of acceleration, as follows:

`a_1=(\Delta v)/(\Delta t)`

Replacing:

`\begin{gathered} a_1=\frac{v_1-u_1_{}}{t_1}=(10.7-0)/(5.1)=2.1m/s^2 \\ a_2=\frac{v_2_{}-u_2}{t_2}=(25-0)/(9)=2.8m/s^2 \end{gathered}`

The acceleration of the cyclist is 2.1 m/s^2, it is not higher than the acceleration of the car, since it is equal to 2.8 m/s^2