Question

I need the ratio for sin (p) and cos (t)

Answer 1

`\sin (P)=(5)/(13)`
`\tan (T)=(12)/(5)`
`\cos (T)=(5)/(13)`

Step-by-step explanation:

Given the below right triangle;

We can go ahead and determine the below trig ratios as seen below;

For sin(P), we'll have;

`\begin{gathered} \sin (P)=\frac{opposite\text{ side to angle P}}{\text{Hypotenuse}}=(5)/(13) \\ \therefore\sin (P)=(5)/(13) \end{gathered}`

For tan(T), we'll have;

`\begin{gathered} \tan (T)=\frac{opposit\text{e side to angle T}}{\text{adjacent side to angle T}}=(12)/(5) \\ \therefore\tan (T)=(12)/(5) \end{gathered}`

For cos(T), we'll have;

`\begin{gathered} \cos (T)=\frac{adjacent\text{ side to angle T}}{\text{hypotenuse}}=(5)/(13) \\ \therefore\cos (T)=(5)/(13) \end{gathered}`