If 0.35 mol of Sodium Chloride and 0.15 mol of Potassium Chloride are added to11.00 L of water, calculate

asked Oct 11, 2023 85.8k views

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answer

a. [Na+] = 0.35mol / 0.011L

= 0.0039 M

b. [K+] = 0.15mol / 0.011L

= 0.0017 M

c. [Cl-] = (0.15+0.35) / 0.011L

= 0.055 M

Lefteris Xris answered Oct 17, 2023

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