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Just need help solving this ( not graded just a review)-example-1

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Given

jenny mixed 4kg of mixed nuts containing 16% of peanuts with 12kg of mixed nuts containing 40% of peanuts .

Find

Percent in the new mixture of peanuts

Step-by-step explanation

we are given 4kg of mixed nuts containing 16% of peanuts

Amount of quantity =


(percentage)/(100)* totalamount

so,


(16)/(100)*4=0.64kg

and also 12kg of mixed nuts containing 40% of peanuts .

so,


(40)/(100)*12=4.8kg

so,total weight


0.64+4.80=5.44kg

let total mass pf mixture containing x % peanuts.

so,


\begin{gathered} (5.44)/(16)=(x)/(100) \\ 34=x \end{gathered}

Final Answer

Percent in the new mixture of peanuts = 34%

User Jrichner
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