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How do I write an equation of a line passing through

How do I write an equation of a line passing through-example-1
User Raye
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1 Answer

3 votes
Answer:

The equation is:


y=(1)/(2)x+2

Step-by-step explanation:

Given the point (2, 3), and the equation:

y - 4 = -2(x + 3) .............................................(1)


\begin{gathered} y=-2x-6+4 \\ =-2x-2 \end{gathered}

Comparing with the equation of a line:


y_{}=mx+b

where m is the slope, and b is the y-intercept

The slope in (1) is -2

Note that perpendicular lines have their slopes as negative reciprocals of each other.

The negative reciprocal of -2 is 1/2

The equation of a line perpendicular to (1) is:


y=(1)/(2)x+b

Applying the given point (2, 3), we have x = 2, y = 3


\begin{gathered} 3=(1)/(2)(2)+b \\ \\ b=3-1=2 \end{gathered}

The equation is therefore;


y=(1)/(2)x+2

User Vetri
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