Question

Indicate a general rule for the n th term of the sequence. Find a a_g a_1 =2

Answer 1

`\begin{gathered} a_n=2(√(3))^(n-1) \\ \\ a_9=162 \end{gathered}`

Explanation:

Notice that the formula:

`a_n=2(√(3))^(n-1)`

Has the general looking form of a series, and also stands for the a1 given, since:

`a_1=2`

This way, we'll have that:

`\begin{gathered} a_9=2(√(3))^(9-1) \\ \\ \Rightarrow a_9=162 \end{gathered}`