Question

The pair of equations 3x + y + 4 = 0 and -3x - 6y + 1 = have * A unique solution*exactly two solutions*infinitely many solutions*no solutions

Answer 1

Given:

3x + y + 4 = 0

-3x - 6y + 1 = 0

Required:

To calculate which option is correct

Step-by-step explanation:

The given equations are

3x + y + 4 = 0

3x - 6y + 1 = 0

a1=3; b1=1 ; c1=4

a2=-3;b2=-6 ; c2=1

`(a1)/(a2)=(3)/(-3)=-1`
`(b1)/(b2)=(1)/(-6)=-(1)/(6)`
`(c1)/(c2)=(4)/(1)=4`
`(a1)/(a2)\\e(b1)/(b2)\\e(c1)/(c2)`

which means it is A unique solution

Required answer:

Option A