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I need help with getting the answer to this question-example-1

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In this problem, we want to rewrite an equation from point-slope form to slope-intercept form, given a point and the slope.

In point-slope form, we have:


y-y_1=m(x-x_1)

Using the point and slope provided,


(x,y)=(-3,5);m=-2

we can substitute into the form:


\begin{gathered} y-5=-2(x-(-3)) \\ \\ y-5=-2(x+3) \end{gathered}

To write it into slope-intercept form, we need to simplify the right-hand side, then isolate the y-variable.

Apply the distributive property:


\begin{gathered} y-5=-2(x)-2(3) \\ \\ y-5=-2x-6 \end{gathered}

Add 5 to both sides:


\begin{gathered} y-5+5=-2x-6+5 \\ \\ y=-2x-1 \end{gathered}

So, the slope intercept form is


\boxed{y=-2x-1}

User Shishir Anshuman
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