The formula we are going to use is:
![\rho=(m)/(V)](https://img.qammunity.org/2023/formulas/chemistry/high-school/9kur6nx1zv5yn6pmaen9vo51nz3vc8vp9y.png)
Where
p is density, in g/mL
m is mass, in grams
V is volume, in mL or cm^3
Density is given and we have to find the volume.
The gold bar is in a shape of rectangular prism, so we need to multiply the width, height, and length (given) of the gold bar to find its volume. Let's do it:
![\begin{gathered} V=1.2*1.6*23 \\ V=44.16\operatorname{cm}^3 \end{gathered}]()
Now, we substitute and solve for m, the mass (weight) in grams:
![\begin{gathered} \rho=(m)/(V) \\ 19.3=(m)/(44.16) \\ m=19.3*44.16 \\ m=852.288\text{grams} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/j91k3vmad5bmbh5py0vr0nwuxdzdb5rkax.png)
The mass is abut 852.29 grams