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If Gold has a density of 19.3 g/mL, How much would a bar of gold that is 1.20 cm wide, 1.60 cm high and 23.0 cm long weigh in grams?

User Ramesh Sen
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1 Answer

2 votes

The formula we are going to use is:


\rho=(m)/(V)

Where

p is density, in g/mL

m is mass, in grams

V is volume, in mL or cm^3

Density is given and we have to find the volume.

The gold bar is in a shape of rectangular prism, so we need to multiply the width, height, and length (given) of the gold bar to find its volume. Let's do it:


\begin{gathered} V=1.2*1.6*23 \\ V=44.16\operatorname{cm}^3 \end{gathered}

Now, we substitute and solve for m, the mass (weight) in grams:


\begin{gathered} \rho=(m)/(V) \\ 19.3=(m)/(44.16) \\ m=19.3*44.16 \\ m=852.288\text{grams} \end{gathered}

The mass is abut 852.29 grams

User Pankaj Saha
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