Given:
![L:(x+10)/(2)=y=(z-1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/oevubytyvh88kpccj9a3ovew1dz2c2mlso.png)
Required:
We need to find the point that lies on the given line and director vector.
Step-by-step explanation:
Consider the equation.
![(x+10)/(2)=y](https://img.qammunity.org/2023/formulas/mathematics/college/5dked1uk4ttuyk645jiktlqnl1z89su524.png)
Set x =2 and substitute in the equation.
![(2+10)/(2)=y](https://img.qammunity.org/2023/formulas/mathematics/college/gl2akmv6n428jy46hdfydcpx6vrvv1yejt.png)
![(12)/(2)=y](https://img.qammunity.org/2023/formulas/mathematics/college/xm22gzwpv1661zzf3g3ob28zyw5bhlgo5l.png)
![6=y](https://img.qammunity.org/2023/formulas/mathematics/college/4eemwu5wnqr7fdg0tz473gz0alf4y7kkfc.png)
We get y =2
Consider the equation.
![y=(z-1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/1vmk165cjuc5cfhsfn6zjkb5s9us9nipa3.png)
Substitute y =6 in the equation.
![6=(z-1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/iu50x0o6b2eppqfaj9ooiprhza1rmgv2qi.png)
Multiply both sides by 3.
![3*6=3*(z-1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/kyufr82xakxlvgvrzsiwr8dvriyo86wawb.png)
![18=z-1](https://img.qammunity.org/2023/formulas/mathematics/college/tgh90vjciba2dzg00teu24bchndaat2nbi.png)
Add 1 to both sides.
![18+1=z-1+1](https://img.qammunity.org/2023/formulas/mathematics/college/vetgp4kxuds9jt2ahv51egzq8urlggyi4w.png)
![19=z](https://img.qammunity.org/2023/formulas/mathematics/college/ljbl3ngein7eho3prxrs4h7pn13msvh1lh.png)
We get z =19.
The given line passes through the point ( 2,6,19).
![\text{ Set x =0 in the equation }(x+10)/(2)=y.](https://img.qammunity.org/2023/formulas/mathematics/college/qgtuqhifp8h5bwal330jhbzd697tmwwzg2.png)
![(10)/(2)=y](https://img.qammunity.org/2023/formulas/mathematics/college/ezzm0hzqcaov38wqtp4lcvknt4awn5qfbp.png)
![5=y](https://img.qammunity.org/2023/formulas/mathematics/college/87vq0pmjs8hav4tykztlkgo4g82exits78.png)
![\text{ Set y =0 in the equation }(x+10)/(2)=y.](https://img.qammunity.org/2023/formulas/mathematics/college/2xa6avhd3rh50c9h6hsm5xb6do0y24042q.png)
![(x+10)/(2)=0](https://img.qammunity.org/2023/formulas/mathematics/college/7blwsxfy0lv66kneg9s00139y6vqkwopns.png)
![x=-10](https://img.qammunity.org/2023/formulas/mathematics/high-school/ur2xaaq2zem6axkdgdnxs55akb7hzw1704.png)
![Set\text{ y =0 in the equation }y=(z-1)/(3).](https://img.qammunity.org/2023/formulas/mathematics/college/ch6pvwvh0187yv7ixrc72bas1p4u12l7pn.png)
![(z-1)/(3)=0](https://img.qammunity.org/2023/formulas/mathematics/college/4vg4y91vp9cjv1gd33lxx2u0gjg9f6tjyy.png)
![z-1=0](https://img.qammunity.org/2023/formulas/mathematics/college/f58598ysgoqa22hqwxg90wqahkwxs361n8.png)
![z=1](https://img.qammunity.org/2023/formulas/mathematics/college/qv199bxnq91oqqcyb3rnfy3t87ndj3ovyl.png)
The director vector is (-10, 5.1).
Final answer:
The given line passes through the point ( 2,6,19).
The director vector is (-10, 5.1).