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|4x-1|=6 Solve the solution set is

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We need to solve the next given expression:


\lvert4x-1\rvert=6

Now, we need to use the next absolute rule:

if lul = a, where a>0

Then, u = a or u = -1

Therefore, we have the next :


\begin{gathered} 4x-1=6 \\ or \\ 4x-1=-6 \end{gathered}

Solve for x . Therefore:


4x-1=6
4x=6+1
x=(7)/(4)

or


4x-1=-6
4x=-6+1
x=-(5)/(4)

Hence, x can take the next two values:


x=-(5)/(4),(7)/(4)

User Nethken
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