Question

Please help ASAP!!!!!

Answer 1

The rational function is

`(2x+2)/(x^2-1)`

For calculate vertical asymptote we need to find which value of x make zero the denominator

`\begin{gathered} x^2-1=0 \\ (x+1)(x-1)=0 \\ x=1 \\ x=-1 \end{gathered}`

And for the numerator

`\begin{gathered} 2x+2 \\ 2(x+1) \\ \end{gathered}`

The whole expression

`\begin{gathered} (2(x+1))/((x+1)(x-1)) \\ (2)/((x-1)) \end{gathered}`

In this case, the vertical asymptote is at -1