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What is the slope of the line created by this equation?Round you answer out to two decimal places.5x+5y=10

What is the slope of the line created by this equation?Round you answer out to two-example-1

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SOLUTION

Write out the equation given


5x+5y=10

To obtain the slope of the line, we need to write the equation in the slope-intercept form


\begin{gathered} y=mx+c \\ \text{where m=slope, c=intercept on y} \end{gathered}

To write in slope - intercept form, we nake y the subject of the formula from the equation given.


\begin{gathered} 5x+5y=10 \\ \text{divide through by 5, we have } \\ (5x)/(5)+(5y)/(5)=(10)/(5) \\ x+y=2 \end{gathered}

Subtract x from both sides, we have


\begin{gathered} x+y=2 \\ x-x+y=2-x \\ y=-x+2 \end{gathered}

The equation of the line becomes


\begin{gathered} y=-x+2 \\ \text{where slope,m=-1} \end{gathered}

Therefore

Answer: Slope = -1

User Vane Trajkov
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