Question

I need help on on this answer can you help me

Answer 1

The answer is Option C.

EXPLANATION :

Using the quadratic formula in finding the values of x :

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

where a, b and c are the coefficients of the quadratic function.

`-3x^2-4x-4=0`

a = -3, b = -4 and c = -4

`\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(-3)(-4)}}{2(-3)} \\ x=\frac{4\pm\sqrt[]{16-48}}{-6} \\ x=\frac{-4\pm\sqrt[]{-32}}{6} \\ x=\frac{-4\pm4i\sqrt[]{2}}{6} \\ x=\frac{-2\pm2i\sqrt[]{2}}{3} \end{gathered}`

Note that i = √-1