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Probability of independent eventsA spinner has 10 equally sized sections, 7 of which are gray and 3 of which are blue. The spinner is spun twice. What is the probability that the first spin landson gray and the second spin lands on blue?Write your answer as a fraction in simplest form.

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Thouse events are independent, so we can calculate them separately and the final rpobability will be the product of them.


P(A\, and\, B)=P(A)\cdot P(B)

The first event, say A, is of landing on gray. Since 7 out of the 10 are gray, the probability is:


P(A)=(7)/(10)

Th second event, B, is of landing on blue. Since 3 out of the 10 are blue, the probability is:


P(B)=(3)/(10)

So, the probability of both is:


P(A\, and\, B)=P(A)\cdot P(B)=(7)/(10)\cdot(3)/(10)=(21)/(100)

User Gaurav Pandey
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