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Fill in the blank __(x+6)+8(x+6) =4x+24

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We want to fill in the blank in the equation;

let's represent the blank with a.


_{}a(x+6)+8(x+6)=4x+24

Let's factorize the right side of the equation.


\begin{gathered} a(x+6)+8(x+6)=4x+24 \\ a(x+6)+8(x+6)=4(x+6) \end{gathered}

and also the left side;


\begin{gathered} a(x+6)+8(x+6)=4(x+6) \\ (a+8)(x+6)=4(x+6) \end{gathered}

Then let's divide both sides by (x+6);


\begin{gathered} (a+8)(x+6)=4(x+6) \\ ((a+8)(x+6))/((x+6))=(4(x+6))/((x+6)) \\ (a+8)=4 \end{gathered}

Then we can solve for a in the resulting equation.

subtract 8 from both sides.


\begin{gathered} a+8=4 \\ a+8-8=4-8 \\ a=-4 \end{gathered}

Therefore, the value to fill into the blank is -4


-4(x+6)+8(x+6)=4x+24

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