Question

Please help a girl out, cannot be written as a fraction

Answer 1

Given:

`9n^2-23n+20=3n^2`
`\begin{gathered} \text{Quadratic formula ,} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}\ldots\ldots(1) \end{gathered}`

The given equation can be written as,

`\begin{gathered} 6n^2-23n+20=0 \\ \text{Compare it with ax}^2+bx+c=0 \\ a=6,b=-23,c=20 \\ n=(-\left(-23\right)\pm√(\left(-23\right)^2-4\cdot\:6\cdot\:20))/(2\cdot\:6) \\ n=(-\left(-23\right)\pm\:7)/(2\cdot\:6) \\ n=(-\left(-23\right)+7)/(2\cdot\:6),\: n_{}=(-\left(-23\right)-7)/(2\cdot\:6) \\ n=(5)/(2),\: n=(4)/(3) \\ n=2.5,n=1.3333 \end{gathered}`
`\begin{gathered} \text{Solutio is (}(5)/(2),(4)/(3)) \\ \text{That is (2.5,1.3333)} \end{gathered}`

The solution of given equation is n= 2.5, 1.333.