Question

Find the center of the circle whose equation is (x+11)^2+(y-7)^2=121

Answer 1

Given the following equation of a circle:

`\left(x+11\right)^2+\left(y-7\right)^2=121`

The general equation of the circle is as follows:

`(x-h)^2+(y-k)^2=r^2`

Where: (h,k) is the center of the circle and (r) is the radius of the circle

We will compare the two equations

So, h = -11, and k = 7 and r = √121 = 11

so, the answer will be:

The center of the circle = (-11, 7)