Question

I need help finding the answers. I don’t need a step-by-step explanation just the answer please. Thank you.

Answer 1

Given the figure of a right-angle triangle and the indicated angle θ

As shown, the hypotenuse = 7

And the opposite side = 4

We will use the Pythagorean theroem to find the adjacent side:

`adjacent=√(7^2-4^2)=√(49-16)=√(33)`

Now, we will find cot θ, sec θ, and cos θ as follows:

`\begin{gathered} \cotθ=(adjacent)/(opposite)=(√(33))/(4) \\ \\ \secθ=(hypotenuse)/(adjacent)=(7)/(√(33))=(7√(33))/(33) \\ \\ \cosθ=(adjacent)/(hypotenuse)=(√(33))/(7) \end{gathered}`

So, the answer will be:

`\begin{gathered} \cotθ=(√(33))/(4) \\ \\ \secθ=(7√(33))/(33) \\ \\ \cosθ=(√(33))/(7) \end{gathered}`