Question

A circus stuntman holds himself straight out by his arms from a vertical pole. If the stuntman's center of gravity is located 0.75 m away from the pole and he weights 650 N, how much force do is arms have to apply if they exert their force upwards at 0.10 m away from the pole? [4875 N]

Answer 1

Answer: 4875 N

Step-by-step explanation:

Given

Stuntman weight is
`W=650\ N`

His center of gravity is located at
`x=0.75\ m` away from pole

If he applies an upwards force at 0.10 m away from the pole

Suppose F is the applied force

To remain vertical, the torque of weight must be canceled by the vertical force

`\Rightarrow 650* 0.75-F* 0.10=0\\\\\Rightarrow 650* 0.75=F* 0.10\\\\\Rightarrow F=(487.5)/(0.10)=4875\ N`