So we have two conditions, the first one is that the length (L) of the swimming area is 6 meters more than the width (W) so:

and the other condition is that the area is 180 square meters so we can writte it like:

Now we have 2 equations and 2 ingognitas so we can replace the first equation into the second equation like this:

and we solve for W so
![\begin{gathered} 180=6W^2^{} \\ W^2=(180)/(6)=30 \\ W=\sqrt[]{30}=5.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z3svdmdxrkwgm8rnx1brqzwfvxhltj4kuu.png)
Now with the value of W we can replace it in the first equation so:

so:

The dimensions are:
