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Please help me with the question below (also please explain).

Please help me with the question below (also please explain).-example-1
User Learnin
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To find the surface area of the given figure identify all the faces on the figure, calculate the area of each face and then sum the areas:

Measures in red

Number of faces in green, total faces 9

Area of a triangle:


A=(1)/(2)bh

Area of a rectangle:


A=bh

Area of faces 1 and 2(rectangles):


\begin{gathered} A_1=A_2=20in*11in \\ A_1=A_2=220in^2 \end{gathered}

Area of faces 3 and 4 (triangles):


\begin{gathered} A_3=A_4=(1)/(2)(12in)(9in) \\ \\ A_3=A_4=54in^2 \end{gathered}

Area of faces 5 and 6 (rectangles):


\begin{gathered} A_5=A_6=12in*5in \\ A_5=A_6=60in^2 \end{gathered}

Area of faces 7 and 8 (rectangles):


\begin{gathered} A_7=A_8=20in*5in \\ A_7=A_8=100in^2 \end{gathered}

Are of face 9 (rectangle):


\begin{gathered} A_9=20in*12in \\ A_9=240in^2 \end{gathered}

Total surface area:


\begin{gathered} SA=A_1+A_2+A_3+A_4+A_5+A_6+A_7+A_8+A_9 \\ \\ SA=220in^2+220in^2+54in^2+54in^2+60in^2+60in^2+100in^2+100in^2+240in^2 \\ \\ SA=1108in^2 \end{gathered}

Then, the surface area of the given figure is 1108 square inches

Please help me with the question below (also please explain).-example-1
User FiberOptics
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