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A line is perpendicular to the line given by the equation 9y = x + 13. What is theslope of the perpendicular line?

User Hoatzin
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the slope of the perpendicular line is -9



Step-by-step explanation:

Given equation: 9y = x + 13

Rewritting in the form of slope-intercept form: y = mx + c

We divide both sides by the coefficient of y:

9y/9 = x/9+ 13/9

y = x/9 + 13/9

where m = 1/9

c = 13/9

For a line to be perpendicular to another line, the slope of one will be the negative reciprocal of the second slope

Since the slope of the first line = 1/9

reciprocal of 1/9 = 9/1 = 9

negative reciprocal = -9

The slope of the second is the negative reciprocal of the 1st line

Hence, the slope of the second (slope of the perpendicular line) is -9

User Noio
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