f(x) =x² + 2x - 3
The zeros of the function is the x-value for which the function equals to zero.
To find such x-value, simply substitute f(x) =0 and the solve forx
x² + 2x - 3 =0
We can solve using the factorization method
Find two numbers such that its product gives -3 and its sum gives 2.
The numbers are : +3 and -1
Replace the coefficient of x by the two numbers
x² + 3x - x - 3 = 0
x(x+ 3) - 1(x+3) = 0
(x+3)(x- 1) = 0
x+3 = 0 and x- 1 = 0
x = -3 and x= 1
Therefore, the zeros of the functions are: D)(-3,0) and (1,0)