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I don't understand how to do this question. the equation is
g(x) = \pi \sin( (x)/(2) ) + \pi

I don't understand how to do this question. the equation is g(x) = \pi \sin( (x)/(2) ) + \pi-example-1
User Daminetreg
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1 Answer

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We have the next function


g(x)=\pi\sin ((x)/(2))+\pi

the amplitude is π

The natural frequency is


\omega=(1)/(2)

with this, we can calculate the frequency and the period


\omega=2\pi f=(2\pi)/(T)

for frequency


f=(\omega)/(2\pi)=((1)/(2))/(2\pi)=(1)/(4\pi)

the period is


T=(1)/(f)=4\pi

The phase shift is 0

the vertical translation is π

the equation of midline is


y=\pi

The graph of the function is

where g(x) is the graph in red and the midline is the graph in blue

I don't understand how to do this question. the equation is g(x) = \pi \sin( (x)/(2) ) + \pi-example-1
User Sebaferreras
by
7.7k points

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