Question

lilla On a coordinate plane, point J is located at (-1, -2) and point K is located at (8, 10). What is the distance, in units from point J to point K? Enter youh answer in the space provided.

Answer 1

Using the distance formula;

`|d|=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`

From the points given:

x₁=-1 y₁=-2 x₂=8 y₂=10

substitute the values into the formula;

`|d|=\sqrt[]{(8+1)^2+(10+2)^2}`
`=\sqrt[]{9^2+12^2}`
`=\sqrt[]{81+144}`

`=\sqrt[]{225}`
`=15`

The distance is 15 units.