Question

The letters COCONUT are written on 8 cards. A card is chosen, what is the probability that it will be a letter in the word CHOCOLATE?

Answer 1

We have the Word COCONUT and the word CHOCOLATE as we can see the common letter in the word are C, O, T

The probability to obtain a letter that in the word Chocolate is

`P(\text{letter in the word chocolate)=P(C)+P(O)+P(T)}`

where

`\begin{gathered} P(C)=(2)/(7) \\ P(O)=(2)/(7) \\ P(T)=(1)/(7) \end{gathered}`

then we substitute this information

`P(\text{letter in the word chocolate)=}(2)/(7)+(2)/(7)+(1)/(7)=(5)/(7)`

The probability to chose a card that it will be a letter in the word CHOCOLATE is 5/7