Let M be Emma's speed and E be Emily's speed. Since Emma rode 8 times as fast as Emily, we can write it as
![M=8* E](https://img.qammunity.org/2023/formulas/mathematics/college/zbvfj0ys3e5bqprlsfedxj2bl4r0amvsqp.png)
Now, we know that she rode 48 km in 4 hours less than it took Emily to ride 36 miles. This means that
![\begin{gathered} \\ \\ 48km=M*(t-4hours) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/l0amt1j1oq98vtl7c3mlxv6aspxbqx01bt.png)
and
![36\text{miles}=E*(t)](https://img.qammunity.org/2023/formulas/mathematics/college/z0jkbkmsyb74h6fpotsr0lndvv4b180esj.png)
where t denotes the time in which they rode the same distance.
From the second equation,we have
![\begin{gathered} \\ (t-4)=(48)/(M)\ldots(A) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/82n5ov9l3qevl4jhaegcgvknqvyunsz6o7.png)
and for the third equation, we have
![\begin{gathered} \\ t=(36)/(E)= \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ttyb9j9rqfqhz7tf7ytrbqn8h5ka83az3v.png)
Now, we need to convert units, from miles to kilometers. We know that 1miles is equal to 1.6km, then we get
![\begin{gathered} \\ 36\text{miles}=36\text{miles(}\frac{1.6\operatorname{km}}{1mile})=57.6\text{ km} \end{gathered}]()
then, our last equation is equivalent to
![t=(57.6)/(E)\ldots(B)](https://img.qammunity.org/2023/formulas/mathematics/college/jakk7b1rvoi8hw7srfp9uwntmkzhxdqnx7.png)
By substituting equation B into equation A, we have
![(57.6)/(E)-4=(48)/(M)\ldots(C)](https://img.qammunity.org/2023/formulas/mathematics/college/nwpqbf6bk87i9vqegn5kglet367nk56ryo.png)
Then, we have 2 equations in 2 unknows, that is, our first equation and equation C. Then, By substituting our first equation into equation C, we have
![\begin{gathered} (57.6)/(E)-4=(48)/(8\cdot E) \\ or \\ (57.6)/(E)-4=(6)/(E) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m82qmmh6liv6ffmcz8yzdoffqyxz4orhzn.png)
By moving the right hand side to the left hand side and -4 to the right hand side, we have
![(1)/(E)(57.6-6)=4](https://img.qammunity.org/2023/formulas/mathematics/college/h0dvqoepk2uqxghtpiiupbyx9ciciiapxy.png)
which gives
![\begin{gathered} \\ (51.6)/(E)=4 \\ E=(51.6)/(4) \\ E=12.9(\frac{\operatorname{km}}{hour}) \end{gathered}]()
with this result, we can find M by substituting this values into our first equation, that is,
![\begin{gathered} M=8* E \\ M=8*12.9 \\ M=103.2(\frac{\operatorname{km}}{hour}) \end{gathered}]()
Then, for the first question How fast did each of them ride ? The answer is
![\begin{gathered} \text{Emma's sp}eed=103.2\text{ }\frac{\operatorname{km}}{hour} \\ \text{Emily's sp}eed=12.9\text{ }\frac{\operatorname{km}}{hour} \\ \end{gathered}]()
Now, in order to find how long they ride, we need to find the time t. We can find it by substituting E into equation B, that is
![\begin{gathered} t=(57.6)/(E) \\ t=(57.6)/(12.9) \\ t=4.46\text{ hour} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qeh718bsy64yksy0o6orqaub1be0ymj5xk.png)
Then, the distance is
![103.2(\frac{km}{\text{hour}})(4.46\text{hour)}=460.8\text{ km}](https://img.qammunity.org/2023/formulas/mathematics/college/mtixey2yot3p9e59tedm22to8ezhr9be4p.png)
then, How long did they ride ? 460.8 kilometers