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6. Find the measure of oneinterior angle of a regular 30-gon.

User Tom
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The sum of the interior angles of a polygon is given by:


\text{Sum}=(n-2)*180

Where n is the number of sides of the polygon.

A regular 30-gon has 30 sides, then the sum is:


\begin{gathered} \text{Sum}=(30-2)*180 \\ \text{Sum}=28*180 \\ \text{Sum}=5040 \end{gathered}

Now, we have to divide the total sum by the number of angles, then:


(5040)/(30)=168

Answer: One interior angle of a regular 30-gon measures 168°.

User Wig
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