Question

Directions: Fill in the blank measurements1. (triangle) Base=32mm Height:35mmArea:___2.(Parallelogram)Area:168yd^2 Height:8ydBase:-----

Answer 1

Question 1

Given:

Base of triangle, b = 32 mm

Height of triangle, h = 35 mm

Let's find the area of the triangle.

To solve for the area, apply the formula:

`\text{Area of triangle = }(1)/(2)\ast b\ast h`

Thus, we have:

`\begin{gathered} \text{Area = }(1)/(2)\ast32\ast35 \\ \\ \text{Area = 16}\ast35 \\ \\ \text{ Area = 560 mm}^2 \end{gathered}`

Area: 560 mm²

• Question 2:

Given:

Area of parallelogram, A = 168 yd²

Height of parallelogram, h = 8 yd

Let's find the base, b, of the parallelogram.

To find the base, apply the area of a parallelogram formula:

`\text{Area}=b\ast h`

Input values into the formula:

`168=b\ast8`

Let's solve for b.

Divide both sides by 8:

`\begin{gathered} (168)/(8)=(b\ast8)/(8) \\ \\ 21=b \\ \\ b=21 \end{gathered}`

Therefore, the base of the parallelogram is 21 yards

ANSWER:

• 1. Area: ,560 mm,²

• 2. Base: ,21 yd