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For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 30 N acts on a certain object, the acceleration of the object is 10 m/s. If the acceleration of the object becomes 3 m's>, what is the force? > Х 5 ? I Don't Know Submit Access 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center 44°F Claudy

User MooingRawr
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The Solution:

We are required to find the force.


\begin{gathered} F\propto a \\ \text{This implies that:} \\ F=ka \end{gathered}

In this case,

F= force=30 N

a = acceleration = 3m/s

k = constant of proportionality = ?

We shall find the constant k by substituting the above values in the formula.


\begin{gathered} F=ka \\ 30=k(10) \end{gathered}

Dividing both sides by 10, we get


k=(30)/(10)=3

So,

The formula for finding Force is:


F=3a

To find the Force when a = 3m/s, we shall substitute 3 for a in the formula.


F=3*3=9N

Therefore, the correct answer is 9 N

User Eyad Bereh
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