Laws of exponent : multiplication and power to a power(x2y3) ⁵

asked Mar 22, 2023 90.0k views

4 votes

by Blum

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6 votes

we have

$\mleft(x^2y^3\mright)^5$

Apply the laws of exponent

$(x^2y^3)^5=(x^2)^5\cdot(y^3)^5$
$(x^2)^5\cdot(y^3)^5=x^((2\cdot5))\cdot y^((3\cdot5))$
$x^((10))\cdot y^((15))$

Machta answered Mar 26, 2023

5.3k points

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