90.0k views
4 votes
Laws of exponent : multiplication  and power to a power(x2y3) ⁵

User Blum
by
8.2k points

1 Answer

6 votes

we have


\mleft(x^2y^3\mright)^5

Apply the laws of exponent


(x^2y^3)^5=(x^2)^5\cdot(y^3)^5
(x^2)^5\cdot(y^3)^5=x^((2\cdot5))\cdot y^((3\cdot5))
x^((10))\cdot y^((15))

User Machta
by
8.7k points

Related questions

1 answer
4 votes
187k views
1 answer
0 votes
102k views
asked Jun 9, 2023 109k views
KingFu asked Jun 9, 2023
by KingFu
7.5k points
1 answer
5 votes
109k views