Question

Find the factors and zeros of 6x^2 +8x-28=2x^2 + 4

Answer 1

First solve the equation:

6x^2 + 8x -28 = 2x^2 + 4

=> 6x^2 - 2x^2 + 8x - 28 -4 = 0 => 4x^2 + 8x - 32 = 0

Extract common factor 4:

=> 4[x^2 + 2x - 8] = 0

Now factor the polynomial:

4(x + 4) (x - 2) = 0

=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.

So the answer is the option B: 4(x + 4)(x - 2); {-4, 2}

HOPE THIS HELPS! :D