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How many bushels will there been in the figure hold? (1 cu ft≈ 1.24 bushels)

How many bushels will there been in the figure hold? (1 cu ft≈ 1.24 bushels)-example-1
User Voy
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1 Answer

1 vote

Answer:

151.93 bushels

Step-by-step explanation:

First, let's find the volume of the truncated cone using the following equation


V=(1)/(3)\pi h(r^2+rR+R^2)

Where h is the height of the cone, r is the smallest radio and R is the largest radio. So, replacing h = 4 ft, r = 1.5 ft and R = 4.5 ft, we get:


\begin{gathered} V=(1)/(3)(3.14)(4)((1.5)^2+(1.5)(4.5)+(4.5)^2) \\ V=(1)/(3)(3.14)(4)(29.25) \\ V=122.52ft^3 \end{gathered}

Because the radius is half the diameter, so r = 3ft/2 = 1.5 ft and R = 9ft/2 = 4.5 ft.

Now, we know the volume in cubic feet. To find the volume in bushels, we will use the conversion factor 1 ft³ = 1.24 bushels.


122.52ft^3*\frac{1.24\text{ bushels}}{1ft^3}=151.93\text{ bushels}

Therefore, the answer is 151.93 bushels

User Kery Hu
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