Question

Beverage A and Beverage B are sold in identical cans. Beverage A is 8% sugar. the portian of Beverage B that is sugar 0.28. How many times more sugar is in Beverage B than Beverage A?​

Answer 1

Beverage B contains 3.5 times more sugar than Beverage A; this is calculated by dividing the percentage of sugar in Beverage B (28%) by the percentage of sugar in Beverage A (8%).

Step-by-step explanation:

To calculate how many times more sugar is in Beverage B compared to Beverage A, we need to compare their sugar contents. If Beverage A is 8% sugar, this means that for every 100 parts of the beverage, there are 8 parts sugar. Conversely, Beverage B, with a portion of 0.28 sugar, means that 28% of it is sugar since 0.28 is equivalent to 28%.

To determine how many times more sugar Beverage B has compared to Beverage A, we divide the percentage of sugar in Beverage B by the percentage of sugar in Beverage A. So, we have:

Times more sugar = Percentage of sugar in Beverage B / Percentage of sugar in Beverage A

Times more sugar = 28% / 8%

Times more sugar = 0.28 / 0.08

Times more sugar = 3.5

Therefore, Beverage B contains 3.5 times more sugar than Beverage A.

Answer 2

3.5 or 3½ is the answer

im not sure but i hope its helpful