Question

19. 350.0 mL of water was added to 700.0 mL of a 2.0 M solution of NaCl. What was the final concentration of the solution?

Answer 1

Final concentration = 1.33 M

Step-by-step explanation

Given:

Volume 1 = 700.0 mL

Concentration 1 = 2.0 M

Volume 2 = 700.0 + 350.0 mL = 1050 mL

Required: Final concentration

Solution:

To solve this problem, we will use the following equation:

C1V1 = C2V2

C2 = (C1V1)/V2

C2 = (2.0 x 700 mL)/1050

C2 = 1.33 M