Question

Using the quadratic formula solve x=x^2+3x+7

Answer 1

`\begin{gathered} x^2+3x+7=0 \\ x=\frac{-3+\sqrt[]{9-4(1)(7)}}{2}=\frac{-3+\sqrt[]{9-28}}{2}=\frac{-3+\sqrt[]{-19}}{2} \\ x=\frac{-3+\sqrt[]{19}i}{2}\lor x=\frac{-3-\sqrt[]{19}i}{2} \end{gathered}`