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Which equation has no real solutions?(А)2x2+2x+15= 02x2 + 5x - 3=0© x2 + 7x+2=0x2 - 4x + 2 = 0

Which equation has no real solutions?(А)2x2+2x+15= 02x2 + 5x - 3=0© x2 + 7x+2=0x2 - 4x-example-1
User Ulrichb
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1 Answer

1 vote

We are asked to find out which of the given quadratic equation has no real solutions.

Recall that a quadratic equation has no real solutions if the discriminant is less than 0.

The discriminant is given by


d=b^2-4ac

Where a, b, and c are the coefficients of the quadratic equation.

Let us analyze each of the given quadratic equations.

Option A:


2x^2+2x+15=0

The coefficients are

a = 2

b = 2

c = 15

The discriminant is


\begin{gathered} d=b^2-4ac \\ d=2^2-4(2)(15) \\ d=4-120 \\ d=-116 \end{gathered}

As you can see, the discriminant is less than 0, therefore, this quadratic equation has no real solutions.

Therefore, the correct answer is option A.

User Mo Kargas
by
8.2k points
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