If the chords intersect inside the circle, the product of the lengths of the segments of the chords are equal.

Substitute the given values into the equation and then solve for the value of x.

Since the value of KZ is the sum of the length of KL and LZ, we must find the length of LZ. Substitute the value of x into the expression and then simplify.

To obtain the value of KZ, add the lengths of KL and LZ.
