Question

What is the slope of the line with the equation x+1=-y?

Answer 1

The slope intercept form of a line is given by:

`\begin{gathered} y=mx+b \\ \text{where:} \\ m=\text{slope} \\ b=y-\text{intercept} \end{gathered}`

rewrite the equation in its slope intercept form:

`\begin{gathered} x+1=-y \\ \text{ Multiply both sides by -1:} \\ -1(x+1)=-1(-y) \\ y=-x-1 \\ m=-1 \\ b=-1 \end{gathered}`

Therefore, the slope is -1

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using the above procedure:

`\begin{gathered} 9x=6+6y \\ \text{subtract 6 from both sides:} \\ 9x-6=6+6y-6 \\ 9x-6=6y \\ \text{divide both sides by 6:} \\ (6y)/(6)=(9x-6)/(6) \\ y=(3)/(2)x-1 \\ m=(3)/(2) \\ b=-1 \end{gathered}`